4(3x-2)-4=4(x-5)+40

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Solution for 4(3x-2)-4=4(x-5)+40 equation:



4(3x-2)-4=4(x-5)+40
We move all terms to the left:
4(3x-2)-4-(4(x-5)+40)=0
We multiply parentheses
12x-(4(x-5)+40)-8-4=0
We calculate terms in parentheses: -(4(x-5)+40), so:
4(x-5)+40
We multiply parentheses
4x-20+40
We add all the numbers together, and all the variables
4x+20
Back to the equation:
-(4x+20)
We add all the numbers together, and all the variables
12x-(4x+20)-12=0
We get rid of parentheses
12x-4x-20-12=0
We add all the numbers together, and all the variables
8x-32=0
We move all terms containing x to the left, all other terms to the right
8x=32
x=32/8
x=4

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