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4(3x-2)=-2(3-x)
We move all terms to the left:
4(3x-2)-(-2(3-x))=0
We add all the numbers together, and all the variables
4(3x-2)-(-2(-1x+3))=0
We multiply parentheses
12x-(-2(-1x+3))-8=0
We calculate terms in parentheses: -(-2(-1x+3)), so:We get rid of parentheses
-2(-1x+3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
12x-2x+6-8=0
We add all the numbers together, and all the variables
10x-2=0
We move all terms containing x to the left, all other terms to the right
10x=2
x=2/10
x=1/5
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