4(3x-2)=2(6+x1)

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Solution for 4(3x-2)=2(6+x1) equation: 



4(3x-2)=2(6+x1)

We move all terms to the left:

4(3x-2)-(2(6+x1))=0

We add all the numbers together, and all the variables

4(3x-2)-(2(x+6))=0

We multiply parentheses

12x-(2(x+6))-8=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

12x-2x-12-8=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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