4(3x-2)=40-8x

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Solution for 4(3x-2)=40-8x equation: 



4(3x-2)=40-8x

We move all terms to the left:

4(3x-2)-(40-8x)=0

We add all the numbers together, and all the variables

4(3x-2)-(-8x+40)=0

We multiply parentheses

12x-(-8x+40)-8=0

We get rid of parentheses

12x+8x-40-8=0

We add all the numbers together, and all the variables

20x-48=0

We move all terms containing x to the left, all other terms to the right

20x=48

x=48/20

x=2+2/5

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