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4(3x-2)=5(x+1)
We move all terms to the left:
4(3x-2)-(5(x+1))=0
We multiply parentheses
12x-(5(x+1))-8=0
We calculate terms in parentheses: -(5(x+1)), so:We get rid of parentheses
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
12x-5x-5-8=0
We add all the numbers together, and all the variables
7x-13=0
We move all terms containing x to the left, all other terms to the right
7x=13
x=13/7
x=1+6/7
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