4(3x-2)=6(x+1)

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Solution for 4(3x-2)=6(x+1) equation: 



4(3x-2)=6(x+1)

We move all terms to the left:

4(3x-2)-(6(x+1))=0

We multiply parentheses

12x-(6(x+1))-8=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

12x-6x-6-8=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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