4(3x-2)=8(x+1)=100

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Solution for 4(3x-2)=8(x+1)=100 equation: 



4(3x-2)=8(x+1)=100

We move all terms to the left:

4(3x-2)-(8(x+1))=0

We multiply parentheses

12x-(8(x+1))-8=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

12x-8x-8-8=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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