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4(3x-3)(x+4)=0
We multiply parentheses ..
4(+3x^2+12x-3x-12)=0
We multiply parentheses
12x^2+48x-12x-48=0
We add all the numbers together, and all the variables
12x^2+36x-48=0
a = 12; b = 36; c = -48;
Δ = b2-4ac
Δ = 362-4·12·(-48)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60}{2*12}=\frac{-96}{24} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60}{2*12}=\frac{24}{24} =1 $
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