4(3x-3)(x+4)=0

Solution for 4(3x-3)(x+4)=0 equation:

4(3x-3)(x+4)=0

We multiply parentheses ..

4(+3x^2+12x-3x-12)=0

We multiply parentheses

12x^2+48x-12x-48=0

We add all the numbers together, and all the variables

12x^2+36x-48=0

a = 12; b = 36; c = -48;
Δ = b2-4ac
Δ = 362-4·12·(-48)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60}{2*12}=\frac{-96}{24}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60}{2*12}=\frac{24}{24}
=1
$