4(3x-3)+4(5x+2)-5(2x-2)=5(6x-3)+6(4x+3)-189

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Solution for 4(3x-3)+4(5x+2)-5(2x-2)=5(6x-3)+6(4x+3)-189 equation:



4(3x-3)+4(5x+2)-5(2x-2)=5(6x-3)+6(4x+3)-189
We move all terms to the left:
4(3x-3)+4(5x+2)-5(2x-2)-(5(6x-3)+6(4x+3)-189)=0
We multiply parentheses
12x+20x-10x-(5(6x-3)+6(4x+3)-189)-12+8+10=0
We calculate terms in parentheses: -(5(6x-3)+6(4x+3)-189), so:
5(6x-3)+6(4x+3)-189
We multiply parentheses
30x+24x-15+18-189
We add all the numbers together, and all the variables
54x-186
Back to the equation:
-(54x-186)
We add all the numbers together, and all the variables
22x-(54x-186)+6=0
We get rid of parentheses
22x-54x+186+6=0
We add all the numbers together, and all the variables
-32x+192=0
We move all terms containing x to the left, all other terms to the right
-32x=-192
x=-192/-32
x=+6

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