4(3x-3)-2=4(x-2)+26

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Solution for 4(3x-3)-2=4(x-2)+26 equation:



4(3x-3)-2=4(x-2)+26
We move all terms to the left:
4(3x-3)-2-(4(x-2)+26)=0
We multiply parentheses
12x-(4(x-2)+26)-12-2=0
We calculate terms in parentheses: -(4(x-2)+26), so:
4(x-2)+26
We multiply parentheses
4x-8+26
We add all the numbers together, and all the variables
4x+18
Back to the equation:
-(4x+18)
We add all the numbers together, and all the variables
12x-(4x+18)-14=0
We get rid of parentheses
12x-4x-18-14=0
We add all the numbers together, and all the variables
8x-32=0
We move all terms containing x to the left, all other terms to the right
8x=32
x=32/8
x=4

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