4(3x-3)-4=4(x-2)+40

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Solution for 4(3x-3)-4=4(x-2)+40 equation: 



4(3x-3)-4=4(x-2)+40

We move all terms to the left:

4(3x-3)-4-(4(x-2)+40)=0

We multiply parentheses

12x-(4(x-2)+40)-12-4=0



We calculate terms in parentheses: -(4(x-2)+40), so:

4(x-2)+40

We multiply parentheses

4x-8+40

We add all the numbers together, and all the variables

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

12x-(4x+32)-16=0

We get rid of parentheses

12x-4x-32-16=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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