4(3x-3)=3(-2x+2)

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Solution for 4(3x-3)=3(-2x+2) equation: 



4(3x-3)=3(-2x+2)

We move all terms to the left:

4(3x-3)-(3(-2x+2))=0

We multiply parentheses

12x-(3(-2x+2))-12=0



We calculate terms in parentheses: -(3(-2x+2)), so:

3(-2x+2)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

12x+6x-6-12=0

We add all the numbers together, and all the variables

18x-18=0

We move all terms containing x to the left, all other terms to the right

18x=18

x=18/18

x=1

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