4(3x-4)+(x-5)=

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Solution for 4(3x-4)+(x-5)= equation: 



4(3x-4)+(x-5)=

We move all terms to the left:

4(3x-4)+(x-5)-()=0

We add all the numbers together, and all the variables

4(3x-4)+(x-5)=0

We multiply parentheses

12x+(x-5)-16=0

We get rid of parentheses

12x+x-5-16=0

We add all the numbers together, and all the variables

13x-21=0

We move all terms containing x to the left, all other terms to the right

13x=21

x=21/13

x=1+8/13

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