4(3x-4)+6(3x-4)=80

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Solution for 4(3x-4)+6(3x-4)=80 equation: 



4(3x-4)+6(3x-4)=80

We move all terms to the left:

4(3x-4)+6(3x-4)-(80)=0

We multiply parentheses

12x+18x-16-24-80=0

We add all the numbers together, and all the variables

30x-120=0

We move all terms containing x to the left, all other terms to the right

30x=120

x=120/30

x=4

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