4(3x-4)=10-(2x-2)

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Solution for 4(3x-4)=10-(2x-2) equation: 



4(3x-4)=10-(2x-2)

We move all terms to the left:

4(3x-4)-(10-(2x-2))=0

We multiply parentheses

12x-(10-(2x-2))-16=0



We calculate terms in parentheses: -(10-(2x-2)), so:

10-(2x-2)

determiningTheFunctionDomain
-(2x-2)+10

We get rid of parentheses

-2x+2+10

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

12x+2x-12-16=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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