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4(3x-4)=2+(5x+2)
We move all terms to the left:
4(3x-4)-(2+(5x+2))=0
We multiply parentheses
12x-(2+(5x+2))-16=0
We calculate terms in parentheses: -(2+(5x+2)), so:We get rid of parentheses
2+(5x+2)
determiningTheFunctionDomain (5x+2)+2
We get rid of parentheses
5x+2+2
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
12x-5x-4-16=0
We add all the numbers together, and all the variables
7x-20=0
We move all terms containing x to the left, all other terms to the right
7x=20
x=20/7
x=2+6/7
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