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4(3x-4)=3(x+9)+2
We move all terms to the left:
4(3x-4)-(3(x+9)+2)=0
We multiply parentheses
12x-(3(x+9)+2)-16=0
We calculate terms in parentheses: -(3(x+9)+2), so:We get rid of parentheses
3(x+9)+2
We multiply parentheses
3x+27+2
We add all the numbers together, and all the variables
3x+29
Back to the equation:
-(3x+29)
12x-3x-29-16=0
We add all the numbers together, and all the variables
9x-45=0
We move all terms containing x to the left, all other terms to the right
9x=45
x=45/9
x=5
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