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4(3x-5)+1=1+x-11
We move all terms to the left:
4(3x-5)+1-(1+x-11)=0
We add all the numbers together, and all the variables
4(3x-5)-(x-10)+1=0
We multiply parentheses
12x-(x-10)-20+1=0
We get rid of parentheses
12x-x+10-20+1=0
We add all the numbers together, and all the variables
11x-9=0
We move all terms containing x to the left, all other terms to the right
11x=9
x=9/11
x=9/11
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