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4(3x-5)+2=5(2x-7)+x
We move all terms to the left:
4(3x-5)+2-(5(2x-7)+x)=0
We multiply parentheses
12x-(5(2x-7)+x)-20+2=0
We calculate terms in parentheses: -(5(2x-7)+x), so:We add all the numbers together, and all the variables
5(2x-7)+x
We add all the numbers together, and all the variables
x+5(2x-7)
We multiply parentheses
x+10x-35
We add all the numbers together, and all the variables
11x-35
Back to the equation:
-(11x-35)
12x-(11x-35)-18=0
We get rid of parentheses
12x-11x+35-18=0
We add all the numbers together, and all the variables
x+17=0
We move all terms containing x to the left, all other terms to the right
x=-17
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