4(3x-5)+3x=40-5x

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Solution for 4(3x-5)+3x=40-5x equation: 



4(3x-5)+3x=40-5x

We move all terms to the left:

4(3x-5)+3x-(40-5x)=0

We add all the numbers together, and all the variables

4(3x-5)+3x-(-5x+40)=0

We add all the numbers together, and all the variables

3x+4(3x-5)-(-5x+40)=0

We multiply parentheses

3x+12x-(-5x+40)-20=0

We get rid of parentheses

3x+12x+5x-40-20=0

We add all the numbers together, and all the variables

20x-60=0

We move all terms containing x to the left, all other terms to the right

20x=60

x=60/20

x=3

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