4(3x-5)+4(x+2)=20

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Solution for 4(3x-5)+4(x+2)=20 equation:


Simplifying
4(3x + -5) + 4(x + 2) = 20

Reorder the terms:
4(-5 + 3x) + 4(x + 2) = 20
(-5 * 4 + 3x * 4) + 4(x + 2) = 20
(-20 + 12x) + 4(x + 2) = 20

Reorder the terms:
-20 + 12x + 4(2 + x) = 20
-20 + 12x + (2 * 4 + x * 4) = 20
-20 + 12x + (8 + 4x) = 20

Reorder the terms:
-20 + 8 + 12x + 4x = 20

Combine like terms: -20 + 8 = -12
-12 + 12x + 4x = 20

Combine like terms: 12x + 4x = 16x
-12 + 16x = 20

Solving
-12 + 16x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 16x = 20 + 12

Combine like terms: -12 + 12 = 0
0 + 16x = 20 + 12
16x = 20 + 12

Combine like terms: 20 + 12 = 32
16x = 32

Divide each side by '16'.
x = 2

Simplifying
x = 2

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