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4(3x-5)6(x+1)=5(x-2)+11
We move all terms to the left:
4(3x-5)6(x+1)-(5(x-2)+11)=0
We calculate terms in parentheses: -(5(x-2)+11), so:We get rid of parentheses
5(x-2)+11
We multiply parentheses
5x-10+11
We add all the numbers together, and all the variables
5x+1
Back to the equation:
-(5x+1)
4(3x-5)6(x+1)-5x-1=0
We add all the numbers together, and all the variables
-5x+4(3x-5)6(x+1)-1=0
We move all terms containing x to the left, all other terms to the right
-5x+4(3x-5)6(x+1)=1
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