4(3x-5)=-3x+33

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Solution for 4(3x-5)=-3x+33 equation: 



4(3x-5)=-3x+33

We move all terms to the left:

4(3x-5)-(-3x+33)=0

We multiply parentheses

12x-(-3x+33)-20=0

We get rid of parentheses

12x+3x-33-20=0

We add all the numbers together, and all the variables

15x-53=0

We move all terms containing x to the left, all other terms to the right

15x=53

x=53/15

x=3+8/15

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