4(3x-5)=12x-2(x-8)

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Solution for 4(3x-5)=12x-2(x-8) equation: 



4(3x-5)=12x-2(x-8)

We move all terms to the left:

4(3x-5)-(12x-2(x-8))=0

We multiply parentheses

12x-(12x-2(x-8))-20=0



We calculate terms in parentheses: -(12x-2(x-8)), so:

12x-2(x-8)

We multiply parentheses

12x-2x+16

We add all the numbers together, and all the variables

10x+16

Back to the equation:

-(10x+16)



We get rid of parentheses

12x-10x-16-20=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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