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4(3x-5)=2(3x+5)
We move all terms to the left:
4(3x-5)-(2(3x+5))=0
We multiply parentheses
12x-(2(3x+5))-20=0
We calculate terms in parentheses: -(2(3x+5)), so:We get rid of parentheses
2(3x+5)
We multiply parentheses
6x+10
Back to the equation:
-(6x+10)
12x-6x-10-20=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5
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