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4(3x-5)=2(4+6x)
We move all terms to the left:
4(3x-5)-(2(4+6x))=0
We add all the numbers together, and all the variables
4(3x-5)-(2(6x+4))=0
We multiply parentheses
12x-(2(6x+4))-20=0
We calculate terms in parentheses: -(2(6x+4)), so:We get rid of parentheses
2(6x+4)
We multiply parentheses
12x+8
Back to the equation:
-(12x+8)
12x-12x-8-20=0
We add all the numbers together, and all the variables
-28!=0
There is no solution for this equation
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