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4(3x-5)=2(6x-10)
We move all terms to the left:
4(3x-5)-(2(6x-10))=0
We multiply parentheses
12x-(2(6x-10))-20=0
We calculate terms in parentheses: -(2(6x-10)), so:We get rid of parentheses
2(6x-10)
We multiply parentheses
12x-20
Back to the equation:
-(12x-20)
12x-12x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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