4(3x-5)=2(7x+12)

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Solution for 4(3x-5)=2(7x+12) equation: 



4(3x-5)=2(7x+12)

We move all terms to the left:

4(3x-5)-(2(7x+12))=0

We multiply parentheses

12x-(2(7x+12))-20=0



We calculate terms in parentheses: -(2(7x+12)), so:

2(7x+12)

We multiply parentheses

14x+24

Back to the equation:

-(14x+24)



We get rid of parentheses

12x-14x-24-20=0

We add all the numbers together, and all the variables

-2x-44=0

We move all terms containing x to the left, all other terms to the right

-2x=44

x=44/-2

x=-22

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