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4(3x-5)=3(4+2x)
We move all terms to the left:
4(3x-5)-(3(4+2x))=0
We add all the numbers together, and all the variables
4(3x-5)-(3(2x+4))=0
We multiply parentheses
12x-(3(2x+4))-20=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
12x-6x-12-20=0
We add all the numbers together, and all the variables
6x-32=0
We move all terms containing x to the left, all other terms to the right
6x=32
x=32/6
x=5+1/3
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