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4(3x-5)=4(x-10)
We move all terms to the left:
4(3x-5)-(4(x-10))=0
We multiply parentheses
12x-(4(x-10))-20=0
We calculate terms in parentheses: -(4(x-10)), so:We get rid of parentheses
4(x-10)
We multiply parentheses
4x-40
Back to the equation:
-(4x-40)
12x-4x+40-20=0
We add all the numbers together, and all the variables
8x+20=0
We move all terms containing x to the left, all other terms to the right
8x=-20
x=-20/8
x=-2+1/2
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