4(3x-5)=5x(2x+4)

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Solution for 4(3x-5)=5x(2x+4) equation: 



4(3x-5)=5x(2x+4)

We move all terms to the left:

4(3x-5)-(5x(2x+4))=0

We multiply parentheses

12x-(5x(2x+4))-20=0



We calculate terms in parentheses: -(5x(2x+4)), so:

5x(2x+4)

We multiply parentheses

10x^2+20x

Back to the equation:

-(10x^2+20x)



We get rid of parentheses

-10x^2+12x-20x-20=0

We add all the numbers together, and all the variables

-10x^2-8x-20=0

a = -10; b = -8; c = -20;
Δ = b2-4ac
Δ = -82-4·(-10)·(-20)
Δ = -736
Delta is less than zero, so there is no solution for the equation

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