4(3x-5)=6-(2x+7)

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Solution for 4(3x-5)=6-(2x+7) equation: 



4(3x-5)=6-(2x+7)

We move all terms to the left:

4(3x-5)-(6-(2x+7))=0

We multiply parentheses

12x-(6-(2x+7))-20=0



We calculate terms in parentheses: -(6-(2x+7)), so:

6-(2x+7)

determiningTheFunctionDomain
-(2x+7)+6

We get rid of parentheses

-2x-7+6

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

12x+2x+1-20=0

We add all the numbers together, and all the variables

14x-19=0

We move all terms containing x to the left, all other terms to the right

14x=19

x=19/14

x=1+5/14

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