4(3x-5)=7(2x+8)

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Solution for 4(3x-5)=7(2x+8) equation: 



4(3x-5)=7(2x+8)

We move all terms to the left:

4(3x-5)-(7(2x+8))=0

We multiply parentheses

12x-(7(2x+8))-20=0



We calculate terms in parentheses: -(7(2x+8)), so:

7(2x+8)

We multiply parentheses

14x+56

Back to the equation:

-(14x+56)



We get rid of parentheses

12x-14x-56-20=0

We add all the numbers together, and all the variables

-2x-76=0

We move all terms containing x to the left, all other terms to the right

-2x=76

x=76/-2

x=-38

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