4(3x-5)=8x+28

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Solution for 4(3x-5)=8x+28 equation: 



4(3x-5)=8x+28

We move all terms to the left:

4(3x-5)-(8x+28)=0

We multiply parentheses

12x-(8x+28)-20=0

We get rid of parentheses

12x-8x-28-20=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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