4(3x-5)=9x+3(x-2)-14

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Solution for 4(3x-5)=9x+3(x-2)-14 equation: 



4(3x-5)=9x+3(x-2)-14

We move all terms to the left:

4(3x-5)-(9x+3(x-2)-14)=0

We multiply parentheses

12x-(9x+3(x-2)-14)-20=0



We calculate terms in parentheses: -(9x+3(x-2)-14), so:

9x+3(x-2)-14

We multiply parentheses

9x+3x-6-14

We add all the numbers together, and all the variables

12x-20

Back to the equation:

-(12x-20)



We get rid of parentheses

12x-12x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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