4(3x-7)-3=4(x-4)+17

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Solution for 4(3x-7)-3=4(x-4)+17 equation: 



4(3x-7)-3=4(x-4)+17

We move all terms to the left:

4(3x-7)-3-(4(x-4)+17)=0

We multiply parentheses

12x-(4(x-4)+17)-28-3=0



We calculate terms in parentheses: -(4(x-4)+17), so:

4(x-4)+17

We multiply parentheses

4x-16+17

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

12x-(4x+1)-31=0

We get rid of parentheses

12x-4x-1-31=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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