4(3x-7)-4=4(x-4)+32

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Solution for 4(3x-7)-4=4(x-4)+32 equation: 



4(3x-7)-4=4(x-4)+32

We move all terms to the left:

4(3x-7)-4-(4(x-4)+32)=0

We multiply parentheses

12x-(4(x-4)+32)-28-4=0



We calculate terms in parentheses: -(4(x-4)+32), so:

4(x-4)+32

We multiply parentheses

4x-16+32

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

12x-(4x+16)-32=0

We get rid of parentheses

12x-4x-16-32=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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