4(3x-7)-5=4(x-2)+39

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Solution for 4(3x-7)-5=4(x-2)+39 equation:



4(3x-7)-5=4(x-2)+39
We move all terms to the left:
4(3x-7)-5-(4(x-2)+39)=0
We multiply parentheses
12x-(4(x-2)+39)-28-5=0
We calculate terms in parentheses: -(4(x-2)+39), so:
4(x-2)+39
We multiply parentheses
4x-8+39
We add all the numbers together, and all the variables
4x+31
Back to the equation:
-(4x+31)
We add all the numbers together, and all the variables
12x-(4x+31)-33=0
We get rid of parentheses
12x-4x-31-33=0
We add all the numbers together, and all the variables
8x-64=0
We move all terms containing x to the left, all other terms to the right
8x=64
x=64/8
x=8

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