4(3x-7)-5=4(x-2)+39

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Solution for 4(3x-7)-5=4(x-2)+39 equation: 



4(3x-7)-5=4(x-2)+39

We move all terms to the left:

4(3x-7)-5-(4(x-2)+39)=0

We multiply parentheses

12x-(4(x-2)+39)-28-5=0



We calculate terms in parentheses: -(4(x-2)+39), so:

4(x-2)+39

We multiply parentheses

4x-8+39

We add all the numbers together, and all the variables

4x+31

Back to the equation:

-(4x+31)



We add all the numbers together, and all the variables

12x-(4x+31)-33=0

We get rid of parentheses

12x-4x-31-33=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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