4(3x-7)-7=4(x-2)+29

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Solution for 4(3x-7)-7=4(x-2)+29 equation: 



4(3x-7)-7=4(x-2)+29

We move all terms to the left:

4(3x-7)-7-(4(x-2)+29)=0

We multiply parentheses

12x-(4(x-2)+29)-28-7=0



We calculate terms in parentheses: -(4(x-2)+29), so:

4(x-2)+29

We multiply parentheses

4x-8+29

We add all the numbers together, and all the variables

4x+21

Back to the equation:

-(4x+21)



We add all the numbers together, and all the variables

12x-(4x+21)-35=0

We get rid of parentheses

12x-4x-21-35=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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