4(3x-8)+7(x-2)=19-4(3x-1)

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Solution for 4(3x-8)+7(x-2)=19-4(3x-1) equation: 



4(3x-8)+7(x-2)=19-4(3x-1)

We move all terms to the left:

4(3x-8)+7(x-2)-(19-4(3x-1))=0

We multiply parentheses

12x+7x-(19-4(3x-1))-32-14=0



We calculate terms in parentheses: -(19-4(3x-1)), so:

19-4(3x-1)

determiningTheFunctionDomain
-4(3x-1)+19

We multiply parentheses

-12x+4+19

We add all the numbers together, and all the variables

-12x+23

Back to the equation:

-(-12x+23)



We add all the numbers together, and all the variables

19x-(-12x+23)-46=0

We get rid of parentheses

19x+12x-23-46=0

We add all the numbers together, and all the variables

31x-69=0

We move all terms containing x to the left, all other terms to the right

31x=69

x=69/31

x=2+7/31

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