4(3x-8)-4=4(x-2)+28

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Solution for 4(3x-8)-4=4(x-2)+28 equation: 



4(3x-8)-4=4(x-2)+28

We move all terms to the left:

4(3x-8)-4-(4(x-2)+28)=0

We multiply parentheses

12x-(4(x-2)+28)-32-4=0



We calculate terms in parentheses: -(4(x-2)+28), so:

4(x-2)+28

We multiply parentheses

4x-8+28

We add all the numbers together, and all the variables

4x+20

Back to the equation:

-(4x+20)



We add all the numbers together, and all the variables

12x-(4x+20)-36=0

We get rid of parentheses

12x-4x-20-36=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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