4(3x-8)-4x=-32+x

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Solution for 4(3x-8)-4x=-32+x equation: 



4(3x-8)-4x=-32+x

We move all terms to the left:

4(3x-8)-4x-(-32+x)=0

We add all the numbers together, and all the variables

4(3x-8)-4x-(x-32)=0

We add all the numbers together, and all the variables

-4x+4(3x-8)-(x-32)=0

We multiply parentheses

-4x+12x-(x-32)-32=0

We get rid of parentheses

-4x+12x-x+32-32=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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