4(3x-8)=36-6(x+1)

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Solution for 4(3x-8)=36-6(x+1) equation:



4(3x-8)=36-6(x+1)
We move all terms to the left:
4(3x-8)-(36-6(x+1))=0
We multiply parentheses
12x-(36-6(x+1))-32=0
We calculate terms in parentheses: -(36-6(x+1)), so:
36-6(x+1)
determiningTheFunctionDomain -6(x+1)+36
We multiply parentheses
-6x-6+36
We add all the numbers together, and all the variables
-6x+30
Back to the equation:
-(-6x+30)
We get rid of parentheses
12x+6x-30-32=0
We add all the numbers together, and all the variables
18x-62=0
We move all terms containing x to the left, all other terms to the right
18x=62
x=62/18
x=3+4/9

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