4(3x-8)=6-2(x+1)

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Solution for 4(3x-8)=6-2(x+1) equation: 



4(3x-8)=6-2(x+1)

We move all terms to the left:

4(3x-8)-(6-2(x+1))=0

We multiply parentheses

12x-(6-2(x+1))-32=0



We calculate terms in parentheses: -(6-2(x+1)), so:

6-2(x+1)

determiningTheFunctionDomain
-2(x+1)+6

We multiply parentheses

-2x-2+6

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We get rid of parentheses

12x+2x-4-32=0

We add all the numbers together, and all the variables

14x-36=0

We move all terms containing x to the left, all other terms to the right

14x=36

x=36/14

x=2+4/7

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