4(3x-9)-3=4(x-4)+17

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Solution for 4(3x-9)-3=4(x-4)+17 equation:



4(3x-9)-3=4(x-4)+17
We move all terms to the left:
4(3x-9)-3-(4(x-4)+17)=0
We multiply parentheses
12x-(4(x-4)+17)-36-3=0
We calculate terms in parentheses: -(4(x-4)+17), so:
4(x-4)+17
We multiply parentheses
4x-16+17
We add all the numbers together, and all the variables
4x+1
Back to the equation:
-(4x+1)
We add all the numbers together, and all the variables
12x-(4x+1)-39=0
We get rid of parentheses
12x-4x-1-39=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5

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