4(3x-9)-8=4(x-2)+20

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Solution for 4(3x-9)-8=4(x-2)+20 equation: 



4(3x-9)-8=4(x-2)+20

We move all terms to the left:

4(3x-9)-8-(4(x-2)+20)=0

We multiply parentheses

12x-(4(x-2)+20)-36-8=0



We calculate terms in parentheses: -(4(x-2)+20), so:

4(x-2)+20

We multiply parentheses

4x-8+20

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

12x-(4x+12)-44=0

We get rid of parentheses

12x-4x-12-44=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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