4(3x2)=11x+18

Solution for 4(3x2)=11x+18 equation:

4(3x^2)=11x+18

We move all terms to the left:

4(3x^2)-(11x+18)=0

We get rid of parentheses

43x^2-11x-18=0

a = 43; b = -11; c = -18;
Δ = b2-4ac
Δ = -112-4·43·(-18)
Δ = 3217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{3217}}{2*43}=\frac{11-\sqrt{3217}}{86}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{3217}}{2*43}=\frac{11+\sqrt{3217}}{86}
$