4(3x2)=52

Solution for 4(3x2)=52 equation:

4(3x^2)=52

We move all terms to the left:

4(3x^2)-(52)=0

a = 43; b = 0; c = -52;
Δ = b2-4ac
Δ = 02-4·43·(-52)
Δ = 8944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8944}=\sqrt{16*559}=\sqrt{16}*\sqrt{559}=4\sqrt{559}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{559}}{2*43}=\frac{0-4\sqrt{559}}{86}
=-\frac{4\sqrt{559}}{86}
=-\frac{2\sqrt{559}}{43}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{559}}{2*43}=\frac{0+4\sqrt{559}}{86}
=\frac{4\sqrt{559}}{86}
=\frac{2\sqrt{559}}{43}
$