4(3y+-2)=-8

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Solution for 4(3y+-2)=-8 equation: 



4(3y+-2)=-8

We move all terms to the left:

4(3y+-2)-(-8)=0

We add all the numbers together, and all the variables

4(3y-2)-(-8)=0

We add all the numbers together, and all the variables

4(3y-2)+8=0

We multiply parentheses

12y-8+8=0

We add all the numbers together, and all the variables

12y=0

y=0/12

y=0

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