4(3y+-7)=8

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Solution for 4(3y+-7)=8 equation: 



4(3y+-7)=8

We move all terms to the left:

4(3y+-7)-(8)=0

We add all the numbers together, and all the variables

4(3y-7)-8=0

We multiply parentheses

12y-28-8=0

We add all the numbers together, and all the variables

12y-36=0

We move all terms containing y to the left, all other terms to the right

12y=36

y=36/12

y=3

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